Playing in the rain, a little girl tackles a little boy. Just before she tackles him, the boy is running east at 3 m/s and the girl is running south at 4 m/s. After the tackle, the girl holds on and the two slide on the wet grass. Our system consists of just the two children. Immediately after the tackle, what can we say about how the momenta of each child compare?

The momenta of each child cannot be compared.

Explanation:

The expression of the momentum is as follows;

p=mv

Here, p is the momentum, m is the mass of the object and v is the velocity of the object.

It is given in the problem that the given system consists of two children.

Playing in the rain, a little girl tackles a little boy. Just before she tackles him, the boy is running east at 3 m/s and the girl is running south at 4 m/s. After the tackle, the girl holds on and the two slide on the wet grass. Only the velocities of the children are given.

The total momentum of the given system lies between the south of the east. The momenta of each child cannot be calculated as the mass of the children is not given in the given problem. If the masses of the children are the same then the momenta of each child are equal.

The given system has non zero momentum before and after the collision. Then, The conservation of momentum violates here.

Therefore, the momenta of each child cannot be compared.

the device is called “ rocket engine”