An unknown material has a mass
of 5.61 kg, and its temperature
increases by 0.124°C when
1320 J of heat are added. What is
the specific heat of the material?
(Unit = J/(kg*C))

1896.55J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1320 joules

Mass of material = 5.61kg

C = ? (let unknown value be Z)

Φ = 0.124°C

Then, Q = MCΦ

1320J = 5.61kg x Z x 0.124°C

1320J = 0.696kg°C x Z

Z = (1320J / 0.696kg°C)

Z = 1896.55 J/kg°C

Thus, the specific heat of the material is 1896.55J/kg°C

1897.53J/Kg°C

Explanation:

Data obtained from the question include:

M (mass of material) = 5.61 kg

ΔT ( change in temperature) = 0.124°C

Q ( heat) = 1320 J

C (specific heat capacity of the material) =?

Using the formula Q = MCΔT, the specific heat capacity of the material can be obtained as follow:

Q = MCΔT

C = Q / MΔT

C = 1320J/ (5.61 kg x 0.124°C)

C = 1897.53J/Kg°C

Therefore, the specific heat capacity of the material is 1897.53J/Kg°C

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.