Physics, 20.11.2019 15:31 tdyson3p6xvtu

20 ! urgent answer physics ! : )

the output of a certain electric generating station is 2500 mw.

a) determine the energy output of the station each second, hour, day and year.

b. if the station is 41% efficient, how much energy input is required during a single day’s operation?

c. assume that 1.5 x 10 10 kg of water from a nearby lake circulates each day to cool the operating parts of the station. how much warmer is the return water than the intake water assuming that all the waste energy goes to heating the returned water?

Answers: 2

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Answers

2500 MW means

... 2500 megawatts
... 2.5 x 10⁹ watts
... 2.5 x 10⁹ joules per second <== the most useful one.

a).
second ... 2.5 x 10⁹ joules

hour    (2.5 x 10⁹ joule/sec) x (3,600 sec/hour) = 9 x 10¹² joule/hour

day    (9 x 10¹² joule/hour) x (24 hour/day) = 2.16 x 10¹⁴ joule/day

year (2.16 x 10¹⁴ joule/day) x (365 day/year) = 7.884 x 10¹⁶ joule/yr

b).
   2.16 x 10¹⁴ joule/day = 41% of the input

Divide each side by 41%:

   Input energy = (2.16 x 10¹⁴ joule/day) / 0.41

   = 5.2683 x 10¹⁴ joule per day .

c).
The waste energy goes into the water.
That's the other 59% of the daily input.
0.59 x (5.2683 x 10¹⁴ joule per day) = 3.1083 x 10¹⁴ joule / day.

It takes 4179 joules to raise the temperature of 1 kg of water 1°C.

You have 3.1083 x 10¹⁴ joules, which you pump into 1.5 x 10¹⁰ kg
of water. Every 4179 joules raises the temp of 1 kg by 1°C.

My mind is messed up by a lot of drugs for gout today, so I'll leave that
last calculation for you. (And it wouldn't be such a bad idea for you to
check my earlier numbers too.)

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

Ithink it’s 98 because jajajjajansmsmjs

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20 ! urgent answer physics ! : )

the output of a certain electric generating station...