A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student's power output is 200.0 W, how long does it take the student to climb the rope ? How much work does the student do ?

The time taken for the student to climb the rope is 12.25 s.

The work done by the student in climbing the rope is 2,450 J.

The given parameters;

The time taken for the student to climb the rope is calculated as follows;

E = Pt

mgh = 200t

The work done by the student is obtained by applying work-energy theorem;

W = Pt

W = 200 x 12.25

W = 2,450 J

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The time taken by the student to climb is 12.25 seconds and work done is 2450 J.            

Explanation:

Given that,

Mass of the student, m = 50 kg

The student climbs to a height of 5 meters at a constant speed.

The student's power output is 200.0 W, P = 200 W

The power of an object is given by work done divided by time taken. So,

(b) W is work done,

(b)

So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.