A generator has a square coil consisting of 248 turns. The coil rotates at a rate of 755.35 rev/min in a 0.170 T magnetic field. The maximum value of emf generated is 75 V. What is the length of one side of the coil

The length of one side of the coil is 0.15 m.

Explanation:

Given;

number of turns, N = 248 turns

angular velocity, ω = 755.35 rev/min

angular velocity, ω (in rad/s) =  755.35 rev/min x 2π/60 s = 79.1 rad/s

magnetic field strength, B = 0.170 T

maximum value of emf generated, ξ₀ = 75 V

Maximum emf induced in the coil is given as;

ξ₀ = NABω

where;

A is the area of the square coil

A = ξ₀ / NBω

A = 75 / ( 248 x 0.17 x 79.1)

A = 0.0225 m²

Area of square = L x L = L²

L² =  0.0225 m²

L = √ 0.0225

L = 0.15 m

Therefore, the length of one side of the coil is 0.15 m.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.