In a television picture tube the electrons are accelerated from rest through a potential difference V. Just before an electron strikes the screen, its de Broglie wavelength is 8.00 10-12 m. What is the potential difference

V = 23515.53volt

Explanation:

wavelength λ= 1.1 x 10 -11 m

We know λ= h /√ [2mVq]

Where h = Plancks constant

            = 6.625 x 10 -34 J s

        m = mass of electron

           = 9.11 x 10 -31 kg

         q = charge of eectron

           =1.6 x 10 -19 C

From above potential difference V = ( 1/2mq) (h /λ)²

V = 23515.53volt

does anyone know or what?

c. magnitude and direction