A bullet of mass 4.4 g strikes a ballistic pendulum of mass 2.9 kg. The center of mass of the pendulum rises a vertical distance of 8.3 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

844.9 m/s

Explanation:

We are given that

Mass of bullet,m=4.4 g=

1kg=1000 g

Mass of pendulum=m'=2.9 kg

Vertical distance,y=8.3 cm=

1 m=100 cm

We have to find the initial speed of bullet.

According to law of conservation of energy

Change in kinetic energy=Change in potential energy

Initial kinetic energy=0,Initial potential energy=0

Where

It is final velocity after collision.

According to law of conservation of momentum

Initial speed of pendulum,u'=0

u=844.9 m/s

Hence, the initial speed of bullet=844.9 m/s

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