. A marksman holds a rifle of mass mR = 3.50 kg loosely, so it can recoil freely. He fires a bullet of mass mB = 10 g horizontally with a velocity relative to the ground of vBx = 300 m/s. What is the recoil velocity vRx of the rifle? Find kinetic energy of the bullet and rifle right after firing and tell me which gets more kinetic energy

bullet = 450 J

rifle = 1.3 J

So, the kinetic energy of bullet is much more than the kinetic energy of gun.

Explanation:

mass of rifle, mR = 3.50 kg

mass of bullet, mB = 10 g

velocity of bullet, vBx = 300 m/s

Let VG is the recoil velocity of gun.

By using the conservation of momentum

mass of gun x recoil velocity of gun = mass of bullet x velocity of bullet

3.50 x V = 0.01 x 300

V =  0.86 m/s

kinetic energy of bullet, KB = 0.5 x mB x vB²

KB = 0.5 x 0.01 x 300 x 300 = 450 J

kinetic energy of rifle, KG = 0.5 x mG x v²

KG = 0.5 x 3.5 x 0.86 x 0.86 = 1.3 J

So, the kinetic energy of bullet is much more than the kinetic energy of rifle.

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!