A pack of four Arctic wolves are exerting four different forces upon the carcass of a 500 kg dead polar bear. Wolf one is pulling on the bear with a force of 20 Newtons (N) due north. Wolf two is pulling on the bear with a force of 30 N, 30 degrees north of west. Wolf three is pulling on the bear with a force of 25 N due west, and wolf four is pulling on the bear with a force of 35 N, 10 degrees west of south. Determine the net force acting upon the polar bear and the direction of that force measured north of west.

Net force is 86.135 N , N 82.255° W

Explanation:

Resolving all forces vertically and horizontally.

First vertically.

20N = 20sin90 = 20

30N = 30sin(90-30)= 30sin60

=25.981

25N = 25sin0 = 0

35N =- 35sin80= -34.368

Total of vertical =

20+25.981+0-34.368

= 11.613N

For horizontal

20N =- 20cos 90 = 0

30N =- 30cos 30 = -25.981

25N = -25cos0 = -25

35N = -35cos 10 = -34.468

Total horizontal = 0-25.981-25-34.368= -85.349

Resultant force = √(11.613)²+(-85.349)²

= √(134.862) +(7284.452)

= √ 7419.314

= 86.135 N

Tan(tita°) = 11.613/-85.349

Tan(tita°) =- 0.136

tita° = Tan^-1(-0.136)

tita° = -7.745

North of West = 90-7.745

= 82.255°

your answer is, orbit around the nucleus