In the Bohr model of the hydrogen atom, an electron in the 7th excited state moves at a speed of 4.47 104 m/s in a circular path having a radius of 2.59 10-9 m. What is the effective current associated with this orbiting electron

I = 4.38 x 10⁻⁷ A

Explanation:

Given,

speed = 4.47 x 10⁴ m/s

radius of the circular path, r = 2.59 x 10⁻⁹ m

effective current = ?

The current represented by the orbiting electron is equal to

f is the frequency

q is charge of electron

we know,

f = 2.74 x 10¹² Hz

now,

I = 4.38 x 10⁻⁷ A

Hence, the effective current associated with the orbiting electron is equal to I = 4.38 x 10⁻⁷ A

4.4 x 10^-7 A

Explanation:

charge on an electron, q = 1.6 x 10^-19 C

velocity, v = 4.47 x 10^4 m/s

radius, r = 2.59 x 10^-9 m

Let the effective current is i.

According to the definition of current, the rate of flow of charge through the conductor is called current.

i = q / T

where, T is the time period of rotation.

T = 3.64 x 10^-13 s

So, current

i = 4.4 x 10^-7 A

50 inches should be the resultant vector

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.