A record of travel along a straight path is as follows: (a) Start from rest with constant acceleration of 3.9 m/s 2 for 15.3 s; (b) Constant velocity of 59.67 m/s for the next 0.934 min; (c) Constant negative acceleration of −11.1 m/s 2 for 3.71 s. What was the total displacement

Total displacement Is 1410.9945 meters

Explanation:

The total displacement is as follows.

The first part = triangle A

3.9 m/s² for 15.3 sec.

3.9 * 15.3 = 59.67 m/s

Second part = rectangle

15.67 m/s for (0.934*60)sec= 56.04 sec

Third part = triangle B

11.1m/s² for 3.71 sec

11.1 * 3.71 = 41.171 m/s

The area if these shapes gives the displacement.

For A = 1/2(15.3*59.67)

= 456.4755 m

For B = 15.67 * 56.04

= 878.1468 m

For C = 1/2(41.171*3.71)

= 76.372

Total displacement = 456.4755 + 878.1468 + 76.3722

= 1410.9945 meters

there are no correct statementd on the list of choices you provided.

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length