In 1889, at Jubbulpore, India, a tug-of-war was finally won after 2 h 41 min, with the winning team displacing the center of the rope 3.7 m. What was the magnitude of the average velocity of that center point during the contest

The magnitude of the average velocity of that center point during the contest is 0.0229

Explanation:

Given :

Time interval min

Displacement of the rope m

For calculating average velocity of the rope,

Therefore, the magnitude of the average velocity of that center point during the contest is 0.0229

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answerscientific theory;