- A line passing through D(5c, 10) and T[8,40]has a gradient of 3. Find the value of C

- 2/5

Explanation:

Data obtained from the question include

x1 (x coordinate 1)= 5c

x2 (x coordinate 2) = 8

Δx (change in x coordinate) = x2 - x1 = 8 - 5c

y1 (y coordinate 1) = 10

y2 (coordinate 2) = 40

Δy (change in y coordinate) = y2 - y1 = 40 - 10 = 30

m (gradient) = 3

The gradient is also called the slope and it is represented mathematically as:

Gradient = (change in y coordinate)/(change in x coordinate)

M = Δy/Δx

3 = 30/ 8 - 5c

Cross multiply to express in linear form as shown below:

3(8 - 5c) = 30

Clear the bracket

24 - 15c = 30

Collect like terms

- 15c = 30 - 24

- 15c = 6

Divide both side by - 15

c = 6/-15

c = - 2/5

Therefore, the value of c is - 2/5

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