Calculate the absolute value of the magnitude of the impact force on a 60 kg parachutist falling at 10 m/s if the time to stop was 0.7 seconds.

85.7 N

Explanation:

According to Newton's second law of motion, F is equivalent to the product of mass and acceleration, ma where m is the mass of parachute in kilograms and a is acceleration.

Acceleration is defined as the rate of change of velocity per unit time hence expressed as

Where v and u represent the final and initial velocities respectively.

Substituting this into initial equation of f then

For this case, the final velocity is zero since it comes ro rest. Substituting 0 m/s dor v and 10 m/s for u then 0.7 s for t we can deduce that

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

pecialized keyboards