A soccer ball is kicked horizontally off a bridge with a height of 36 m. The ball travels 25 m horizontally before it hits the pavement below. What was the soccer ball's speed when it was first kicked

The speed of the ball is 9.23m/s

Explanation:

Using kinematic equation for the vertical height is given by:

h = Ut + 1/2 gt^2

Where h = 36m as given from the question

g = acceleration due to gravity= 9.81

Initial velocity, U =0

t = time

Substituting into the equation

36 = 0 + 1/2 ×9.81 × t^2

36 = 4.905t^2

36/4.905 = t^2

7.34 = t^2

Sqrt(7.34) = t

2.71 seconds = t

Speed = distance / time

Speed = 25m/ 2.71s

Speed = 9.23m/s

c, 1a hope this

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge