If an object on a horizontal, frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If it is displaced 0.120 m from its equilibrium position and released with zero initial speed, then after 0.800 s its displacement is found to be 0.120 m on the opposite side, and it has passed the equilibrium position once during this interval. Find (a) the amplitude; (b) the period; (c) the frequency. 14.3 . The tip of a tuning fork go

A) 0.120

B) 1.6s

C) 0.625 Hz

Explanation:

Here, X = 0.120 m

x = 0.120 m after t = 0.800 s

A- Amplitude = max displacement from equillibrium position = 0.120 m

B- Period = 2 * 0.800 = 1.6 s

C- Frequency = 1/peroid = 1/1.6

f = 0.625 Hz

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

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