A uniform, solid sphere of radius 4.50 cm and mass 4.50 kg starts with a purely translational speed of 2.00 m/s at the top of an inclined plane. The surface of the incline is 1.00 m long, and is tilted at an angle of 29.0 ∘ with respect to the horizontal. Assuming the sphere rolls without slipping down the incline, calculate the sphere's final translational speed v 2 at the bottom of the ramp.

3.58 m/s

Explanation:

Data:

The plot can be drawn to present the information in the question.

Then the calculations:

mass = 4.50 kg

translational speed = 2 m/s

radius = 4.50 cm

angle  = 29.0 °

Energy at the top of the incline, is calculated as follows:

The next item is the moment of inertia of the solid:

  =

Then the final velocity, is given by:

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.