A- 5 mC charge travels due south under the influence of a 5. N force when placed into a uniform electric field. Determine the magnitude of the electric field.

Electric field will be equal to 1000 N/C

Explanation:

We have given charge

It is given that this charge is in influence of 5N

So electrostatic force F = 5 N

We have to find the electric field

Force on any charge in an electric field is equal to

So

E = 1000 N/C

So electric field/ will be equal to 1000 N/C

1000 N/C

Explanation:

The relation between electric field, electric force and charge is given as

Here E is electric field, F is the electric force and q is the electric charge.

The magnitude of electric field,

Given F = 5.0 N and q =5 mC.

Substitute the given values, we get

|E| = 1000 N/C

Thus , the magnitude of the electric field is 1000 N/C.

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y