An initially uncharged 4.85-?F capacitor and a 7.69-k? resistor are connected in series to a 1.50-V battery that has negligible internal resistance. What is the initial current in the circuit, expressed in milliamperes? Calculate the circuit\'s time constant in milliseconds. How much time, in milliseconds, must elapse from the closing of the circuit for the current to decrease to 2.31% of its initial value? Show in detail how you find elapsed time(t) please!

0.000140530327543 s

Explanation:

V = Voltage = 1.5 V

r = Resistance =

c = Capacitance =

Initial current

Time constant

The current is

The elapsed time is 0.000140530327543 s

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.