102) Consider massive gliders that slide friction- free along a horizontal air track Glider A has a mass of 1 kg, aspeed of 1 m/s, and collides with Glider B that has a mass of 5 kg and is at rest. If they stick upon collision, theirspeed after collision will beA) lm/s. B) 1/6 m/s. C) 1/5 m/s. D) 1/4 m/s. E) none of these.

B. 1/6 m/s

Explanation:

Parameters given:

Mass of first glider, m = 1 kg

Initial speed of first glider, u = 1 m/s

Mass of second glider, M = 5 kg

Initial speed of second glider, U = 0 m/s.

Using the principle of conservation of momentum, we have that:

Total initial momentum = Total final momentum

=> m*u + M*U = m*v + M*V

Where v is the final velocity of the first glider and V is the final velocity of the second glider.

Since they stick upon collision, their final velocities are the same, hence, v = V

m*u + M*U = m*v + M*v

m*u + M*U = (m + M)*v

Also, since the second glider is initially at rest, U = 0

m*u = (m + M)*v

Therefore,

v = (m*u) / (m + M)

v = (1 * 1) / (1 + 5)

v = 1/6 m/s

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explanation:

increase masses, decrease separation