A 500 500500- kg kgstart text, k, g, end text object is accelerating to the right at 10 cm / s 2 10 cm/s 2 10, start text, space, c, m, end text, slash, start text, s, end text, squared. What is the magnitude of the rightward net force acting on it (in Newtons)?

Given Information:

Mass = m = 500 kg

Acceleration = a = 10 cm/s²

Required Information:

Magnitude of rightward net force = F = ?

Magnitude of rightward net force = 50 N

Explanation:

From the Newton's second law of motion

F = ma

Where m is the mass and a is the acceleration

To get force in Newtons first convert 10 cm/s² into m/s²

10/100 = 0.1 m/s²

F = 500*0.1

F = 50 N

Therefore, the magnitude of rightward net force acting on it is 50 Newtons.

Explanation:

Given that,

Mass of object is 500kg

m=500kg

The body accelerates at 10cm/s2

What is the magnitude of force?

The magnitude of force that push or pull a body of mass and causes it to change velocity i.e accelerate

The force is given as

Force= mass × acceleration

F=ma

The unit of mass(m) is kg

The unit of acceleration (a) is m/s²

The unit of Force(F) is Newton

So in the question given the acceleration is in cm/s², so we need to convert it to m/s

So, 1m=100cm

Then, 10cm/s²= 10cm/s² × 1m/100cm

So, a=0.1m/s²

Then applying the formula

F = ma

F = 500 × 0.1

F = 50 newton

The magnitude of force pushing the body forward is F = 50N

the answer would be 32*f

where are the vectors ?