Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless. Puck A is moving to the right at 6 m/s. Puck B has twice the mass as the first puck and is also moving to the right, but at a slower speed of 2 m/s.

1. Kinetic energy is conserved in the collision.
a. True
b. False

2. Puck B will increase its speed after the collision.
a. True
b. False

3. Puck A will increase its speed after the collision.
a. True
b. False

4. Momentum is conserved in the collision.
a. True
b. False

1. False

2. True

3. False

4. True

Explanation:

Conservation of Momentum

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

The total momentum of both pucks at the initial condition is

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

We are given

The total initial momentum is

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

Equating the initial and final momentum

Solving for v'

1. Compute the initial kinetic energy:

The final kinetic energy is

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

Proven

what is the question because that is not a question.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr