Physics, 25.03.2020 05:05 ethan052

In a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 6.7 rev/s in 8.8 s. You lift the lid of the washer and notice that the tub decelerates and comes to a stop in 16.5 s. Assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.

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Answer from: brookcoyanpeus5y

7.095 rev

Explanation: since the motion of the washer is of a constant angular acceleration, then Newton's laws of motion applies.

Recall that

ω = ω0 + αt

Where α = angular acceleration = ?

ω = final angular velocity = 6.7rev/s

ω0 = initial angular velocity = 0 rev/s

t = time taken =8.8s

Since the motion of the dryer starts from rest, ω0 = 0, we have that

ω = αt

6.7 = α(8.8)

α = 6.7/8.8

α = 0.76 rev/s²

This value α = 0.76 rev/s² is a constant value and it is the same all through the motion.

When the lid of the washer was lifted, the motion was of a constant deceleration.

Recall that

θ = ω0t + αt²/2

Where θ = angular displacement

Since the washer is now decelerating, the final velocity (ω= 6.7 rev/s) of the accelerating motion now because the initial velocity of the decelerating motion.

Hence ω0 = 6.7 rev/s, α = - 0.76 rev/s² ( negative sign to denote deceleration) and t = 16.5s

By slotting in the parameters into the formulae, we have that

θ = 6.7 (16.5) + (-0.76)(16.5)²/2

θ = 110.55 - 103.455

θ = 7.095 rev

Answer from: Quest

Football was the fourth deadliest sport with a fatality rate of .81 per 100,000 participants. cheerleading, which has been shown to be the most dangerous activity based on injury data, was not included in the study because it was not classified as a sport.this is my answer because it didn’t give me any sports

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

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In a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maxim...