A 2.98 X 102-kg crate is being pulled across a horizontal surface by a force F which makes an angle of 35.90 above the horizontal. Suppose that the coefficient of kinetic friction is 0.222, what should the magnitude of F be so that the net work done by it and the kinetic frictional force is zero?

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.