Light of intensity 2.00 W/m2 passes through the pupil of one of your eyes and eventually falls on your retina. The radius of the pupil is controlled by the iris. In a human eye, the radius of the pupil can vary from about 1.0 mm to about 3.5 mm. The area of the opening can be calculated from pi (3.1416) times the radius squared. If your pupil is open to a radius of 2.5 mm, how much light energy passes through in one minute

Explanation:

Intensity of light, I = 2 W/m²

radius of pupil open, r = 2.5 mm = 2.5 x 10^-3 m

time, t = 1 min = 60 second

Energy passes, E = intensity x area x time

E = 2 x 3.14 x 2.5 x 2.5 x 10^-6 x 60

E = 2.36 x 10^-3 Joule

the correct choice is a .

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we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .