A 2-ft-high and 5-ft-wide rectangular plate is submerged vertically in the water so that the top is 1 ft below the surface. Express the hydrostatic force against one side of the plate as an integral.

63393.8 lbfeet/sec^2

Explanation:

Recall that the weight density of water is 62.5 lb/ft3

F = PA P = hρg = h x 62.5 x 32.2 A = 5 x dh force= integral of (hρg3 x dy) // 3 is width of plane force= integral of ( 62.5 x 32.2 x 3 x hdh) from 2 to 5 force= 62.5 x 32.2 x 3 x (5^2-2^2)/2 = 63393.8 lbfeet/sec^2

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: