A solid wood door 1.00 mm wide and 2.00 mm high is hinged along one side and has a total mass of 43.0 kgkg . Initially open and at rest, the door is struck at its center by a handful of sticky mud with mass 0.600 kgkg , traveling perpendicular to the door at 14.0 m/sm/s just before impact.

A) Find the angular speed of the door. B) Does the mud make a significant contribution to the moment of inertia?

0.290055248619 rad/s

Explanation:

r =

m denotes the mass

v = Velocity = 14 m/s

Moment of inertia of the door

Angular momentum of the mud

As the angular momentum is conserved we have

The angular speed of the door is 0.290055248619 rad/s

The mud has a mass 0.6 kg it will not have a significant on the door which is 43 kg. The door is significantly heavier than the mud.

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.