A rod 25 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its length and the potential difference between the ends is 10 V. Find the speed of the rod.

v = 666.667 m/s

Explanation:

Given: length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

v = 10 V / (0.06 T× 0.25 m)

v = 666.667 m/s

it becomes positively charged by charging it

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be