A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v . Assume that the magnitude of the acceleration due to gravity is g .

-What is the work (Wd) done on the skydiver, over the distance , by the drag force of the air?

-Find the power (P d) supplied by the drag force after the skydiver has reached terminal velocity v.

The work done on the skydiver over the given distance is .

The power supplied by the drag force after the skydiver has reached terminal velocity is mgv.

The given parameters;

The work done on the skydiver over the given distance is calculated as follows;

The power supplied by the drag force after the skydiver has reached terminal velocity v;

Learn more here:link

a. Wd = ½mv²−mgd

b. Pd = -mgv

Explanation:

The skydiver losses potential energy and gains kinetic energy.

Work done by gravity

W=mg

Therefore, work done by gravity is given as

P.E= weight × height

P.E= mg × d

P.E= mgd

The work done by kinetic energy

K.E=½mv²

Then, the drag work becomes

We=K.E-P.E

We=½mv² - mgd

b. Drag power

Power is given as

Power=force × velocity

The force =weight =mg

g is negative since or is against gravity (upward motion)

Pd=F×v

Pd=-mgv

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.