A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.8 T is directed along the positive z-direction, which is upward.

If the loop is removed from the field region in a time interval of 2.8 ms, find the average emf that will be induced in the wire loop during the extraction process.

The average induced emf is 29.06 V

Explanation:

Given;

radius of the circular loop, r = 12.0 cm = 0.12 m

magnetic field strength, B =  1.8 T

time interval = 2.8 ms = 0.0028 s

Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

where;

B is magnetic field

A is area

t is time

substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

Therefore, the average induced emf is 29.06 V

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

scorpions are,

c.arachnids

  scorpions are animals in the order scorpiones, under the class arachnida, which makes them a distant cousin of spiders

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