A space shuttle of inertia m is attached to a booster rocket that has an inertia nine times greater. This system is moving at a speed of 900 m/s in outer space, as seen by observers in a nearby space station. Then explosive bolts are detonated, separating the shuttle from the rocket and thrusting the shuttle forward at a speed of 200 m/s relative to the rocket. Suppose that the shuttle and the rocket are initially moving in the positive i^ direction

880, 1080

Explanation:

Credit to: https://answers.yahoo.com/activity/questions?show=PtRQOwUgaa NCS, this is their answer not mine please follow them and vote their answer https://answers.yahoo.com/question/index?qid=20200308192732AAh6S7T here as top answer

(M + 9M)*900m/s i^ = 9M*V + M*(V+200m/s) i^

M cancels

9000 m/s i^ = 10V + 200m/s i^

V = 8800 i^ / 10 = 880 m/s i^ ◄ booster rocket

and so the shuttle has v = 1080 m/s i^ ◄

If you find this helpful, please select Favorite Answer!

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

nah.   i'm just sleepy.