Una piedra es lanzada horizontalmente desde una ventana con una velocidad inicial cuya magnitud es de 10m/s y cae al suelo despues de 5 segundos
a que altura se encuentra la ventana?
a que distancia cae la piedra de la base del edificio?

Answers:

a) 122.5 m

b) 50 m

Explanation:

Here we are dealing with projectile motion, where we can use the following two equations that model the parabolic motion of the stone after being thrown from the window:

(1)

(2)

Where:

is the height of the stone when it hits the ground

is the initial height of the stone

is the initial velocity of the stone

since we are told the stone was thrown horizontally

is the time the stone is in air

is the horizontal distance the stone travelled

Knowing this, we can answer the questions:

a)Initial height of the stone:

In this case we will isolate from (1):

(3)

(4)

(5) This is the initial height

b) Horizontal distance:

In this case we will use equation (2):

(6)

(7) This is the horizontal distance

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

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