Please need help with this problem!!

See the explanation below.

Explanation:

Resistance C is connected in parallel with the 120 V voltage source, so we can determine the current through this resistance by the ohm law.

I = V / R

where:

V = voltage [volt]

R = resistance [ohm]

I = 120 / 100

I = 1.2[amp]

The resistors d, e & f, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.

Rt = 400 + 200 + 200 = 800 [ohm]

This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.

I2 = 120 / 800 = 0.15 [amp]

The resistors a & b, are connected in series, therefore you can calculate the total resistance of them by performing an algebraic sum.

Rt2 = 100 + 100 = 200 [ohm]

This total resistance, will be connected in parallel, with the voltage source in this way we can calculate the current that passes through it through the ohm law.

I3 = 120 / 200 = 0.6 [amp]

Now we can write the currents for each of the resistors.

a ) I = 0.6 [amp]

b) I = 0.6 [amp]

c) I = 1.2 [amp]

d) I = 0.15 [amp]

e) I = 0.15 [amp]

f) I = 0.15 [amp]

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.