A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio pulse for each rotation of the star. The period T of rotation is found by measuring the time between pulses. Suppose a pulsar has a period of rotation of T = 0.0922 s that is increasing at the rate of 3.64 x 10-7 s/y. (a) What is the pulsar's angular acceleration

Explanation:

T = Time period = 0.0922 s

Angular speed is given by

Angular acceleration is given by

The pulsar's angular acceleration is

- 8.5 x 10^-12 rad/s²

Explanation:

Time period, T = 0.0922 s

dT / dt = 3.64 x 10^-7 s/year

As we know that

α = dω/dt

where, α is the angular acceleration and ω is the angular velocity

ω = 2π/T

By substituting the values

α = - 8.5 x 10^-12 rad/s²

answer; ///(74) degrees is your answer..

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