Ask Your Teacher A 47.5-turn circular coil of radius 5.45 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0.495 T. If the coil carries a current of 22.5 mA, find the magnitude of the maximum possible torque exerted on the coil.

Explanation:

We are given that

Radius of coil=r=5.45 cm=

Number of turns,N=47.5

Magnetic field=B=0.495 T

Current,I=22.5 mA=

We have to find the magnitude of maximum possible torque exerted on the coil.

We know that

Maximum torque,

Using the formula

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂