2. Carla's favorite ball is bright blue when it is outside in the direct sunlight. Inside, the ball
appears to be almost green. Why does Carla's ball seem to change colors?
A. Color is determined by the density of an object, and Carla's ball became more dense when
she went inside out of the sunlight.
B. Color is determined by the size of an object, and Carla's ball lost air while being played
with, so it was smaller when she went inside.
C. Color is determined by the wavelength of light reflected or absorbed by the object, and the
light changed when Carla went inside.
D. Color is determined by the temperature of an object, and the temperature changed when
Carla went inside out of the sunlight.

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

Can you give more detail