A small but measurable current of 5.8 × 10-10 A exists in a copper wire whose diameter is 3.0 mm. The number of charge carriers per unit volume is 8.49 × 1028 m-3. Assuming the current is uniform, calculate the (a) current density and (b) electron drift speed.

a) J = 8.2×10^-5A/m^2

b) V = 6.07×10^-15m/s

Explanation:

The current density is the ratio of current to area of the wire.

J = i/A

Drift speed is inversly proportional to the square of the radius of the wire.v α 1/r^2

Please find the attached file for the solution

a

explanation:

because they are cartillidge