A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (1.50 m, 5.30 m) while a constant force acts on it. The force has magnitude 7.40 N and is directed at a counterclockwise angle of 104.° from the positive direction of the x axis. How much work is done by the force on the coin during the displacement?

The work done by the force is 35.37 Joules.

Explanation:

Given that,

coin started sliding from origin (0,0) to point (1.50m,5.30m)

therefore displacement of coin along x-axis,x = 1.50m

displacement of coin along y-axis,y = 5.30m

angle between applied force and positive x-axis = 104

applied force = 7.40N

Now we will find

component of force along x-axis

component of force in y direction,

work is done by the force on the coin during the displacement will be given as

So, the work done by the force is 35.37 Joules.

d. air pressure decreases as altitude increases.

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.