A wire with a mass of 1.14 g/cm is placed on a horizontal surface with a coefficient of friction of 0.200. The wire carries a current of 1.41 A eastward and moves horizontally to the north. What are the magnitude and the direction of the smallest magnetic field that enables the wire to move in this fashion?

Explanation:

let this sign be ∅ (titha in degrees)

let coefficient of friction of 0.200 be u

and i be current i= 1.41A

mass m=1.14g/cm m=0.0114g/m

To find the magnetic field from the north will be:

tan ∅= u

∅=

∅=11.3°

The direction:

i L*B cos(∅)=  umg

divide both by iLcos(∅) to find B

B=  where m=

B=

B=

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

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