Town q and town p were 119 km apart. van drove from town q to town p at an average speed of 70 km/h. how much sooner would be have arrived at town p if he had travelled at an average speed of 85 km/h instead?

0.3 hours sooner than the normal time of arrival

Explanation:

Finding the difference in time of arrival of both speed will help know how much sooner.

Given:

Distance = 119 km

Speed 1 = 70 km/h

Speed 2 = 85 km/h

Time = Distance / Speed

For the time taken at the first speed

Time = 119/70

         = 1.7 hours

For the time taken at the second speed

Time = 119/85

        = 1.4 hours

∴ 1.7 hours - 1.4 hours

= 0.3 hours sooner