Two objects of different mass slide down two different ramps without friction. Both objects are released from rest from the same height, but one ramp is much steeper than the other. m1 > m2.

What are the relative speeds of the two masses when they reach the bottom?

They have the same speed

Explanation:

Law of Conservation of Mechanical Energy

In the absence of dissipative forces (like friction, air resistance), the total amount of mechanical energy, in a closed system remains constant. The mechanical energy is the sum of the potential gravitational and kinetic energies:

Where m is the mass of the object, v its speed and h its height.

The first object's mechanical energy just after it's released in the ramp is

Since it's initially at rest

When it reaches the bottom of the ramp, all it mechanical energy becomes kinetic, so

Being v1' the final speed at the bottom of the ramp. Solving for v1'

The second object's mechanical energy just after it's released in the ramp is

Note the height is the same for both objects. Following the same procedure with m2, we get

Or, similarly

We can see both speeds are the same regardless of their masses or the steepness of the ramps they came from

answer and explanation;

there are no components of a physical goal mentioned on the list of choices that you've provided.