Physics, 15.03.2020 18:30 chanavictor2747

What are the three characteristics of an image formed if the object is placed at 2F of a convex lens ?

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Answer from: hailey200127

1. The resulting image is formed at 2F

2. The image formed is real and inverted

3. Magnification is 1

Explanation:

1. The image is formed at 2F

When an object is placed at point 2F of a convex lens, the resulting image will also be located at the point 2F on the other side of the lens.

This to say object length is equal to image length.

Using Equations;

u = object distance from the mirror = 2F

v = image distance from the mirror

f = focal length

$\frac{1}{u} -\frac{1}{v} =\frac{1}{f}$

substitute 2F for u

$\frac{1}{2f} -\frac{1}{v} =\frac{1}{f}$

Therefore $\frac{1}{2f} -\frac{1}{f} =\frac{1}{v}$

$\frac{-1}{2f} =\frac{1}{v}$

And v = -2f

i.e Image is formed at 2F

2. The image formed is real and inverted;

Real image means the image can be placed on a screen, i.e. light rays will converge at a location which exists in reality and this is accompanied by an inversion whereby an upright object forms an image that is upside-down.

3. Magnification is 1;

Magnification of a convex lens is the ratio of an object height to image height OR the ratio of distance of object to distance of image i.e. $\frac{u}{v}$

where u = 2f

and v = 2f

M = 1

Answer from: Quest

false

explanation:

Answer from: Quest

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: $k= \frac{1}{2}mv^2$ where m is the mass of the arrow and v its velocity. all the other options, instead, do not increase the kinetic energy of the system: - pulling farther back on the string : this will just increase the elastic potential energy of the system- holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)- decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

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