An ice cube with mass mi=30 g and temperature T=0℃ completely melts in a cup of water. The mass of the water in the cup is mw=275 g and its initial temperature, before dropping the ice cube in it, is Tw=29℃. Calculate the temperature of the water in the cup at the instant the ice cube has completely melted. The specific heat capacity of water is cw=4.186 J/(g℃) and the latent heat of fusion of ice is Lf=334 J/g.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.