A singly charged positive ion of mass 2.2 x 10-25 kg is moving upwards through a capacitor. The capacitor creates a constant electric field of magnitude 10,000 V/m, and the ion is not deflected due to an external magnetic field of magnitude 1.0 T that points into the page everywhere in space. (A)After it exits the capacitor, is the ion going to be deflected right or left

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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