A current of 23.0 mA is maintained in a single circular loop with a circumference of 1.50 m. A magnetic field of 0.310 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?

0 Nm

Explanation:

The magnetic dipole moment, μ, is the product of the current and the area of the loop.

The torque is given by

where B is the magnetic field and θ is the angle between the field and the loop.

From the question, the field is parallel to the plane of the loop. Hence,

θ = 0°.

The magnitude of torque is 1.28Nm

Explanation: Please see the attachments below

the answer is b ) square root of 5

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