Estimate the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.2 m and is released with a speed of 12 m/s .

229.11 N

Explanation:

Mass of the shot (m) = 7.0 kg

Distance moved by the shot (S) = 2.2 m

Initial velocity of the shot (u) = 0 m/s (assume)

Final velocity of the shot (v) = 12 m/s

First we will determine the acceleration of the shot using the following equation of motion.

So, the acceleration of the shot is 32.73 m/s².

Now, using Newton's second law, the force acting on the shot is equal to the product of mass and acceleration. So,

Force = Mass × Acceleration

Therefore, the average force exerted by the shot-putter is 229.11 N.

a.   mass number from atomic number

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this