How long is a tungsten wire if it has a diameter of 0.191 × 10 − 3 m and a resistance of 3210 Ω ? The resistivity of tungsten is 5.62 × 10 − 8 Ω ⋅ m .

Length of the tungsten = 1636.4 m

Explanation:

Let's first find the cross sectional area of the wire:

Area =

Area =

Area =    m^2

We can solve for the length using the equation of resistance:

Resistance = Resistivity * Length / Area

Length = 1636.4 m

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explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂