The brake pads for a bicycle tire are made of rubber. If a frictional force of 50 N is applied to each side of the tires, determine the average shear strain in the rubber. Each pad has cross-sectional dimensions of 20 mm and 50 mm. Gr

average shear strain in the rubber is 0.25rad

Explanation:

The base has a dimension of 20mm and 50mm.

frictional force is 50 N

using the expressed shear stress,

we will determine τ =

τ  = 50 / 1000

    = 0.05MPa

shear stress  τ = γ .G

τ  = shear stress

γ  = shear strain

G  = 0.20MPa

γ = τ / G

  = 0.05 / 0.20

  = 0.25rad

average shear strain in the rubber is 0.25rad

the answer would be c. motion and direction

i hope this : )

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2