A 0.250-kg ice puck, moving east with a speed of 5.30m/s , has a head-on collision with a 0.900-kg puck initially at rest. Assume that the collision is perfectly elastic.
A. What is the speed of the 0.250-kg puck after the collision?Express your answer to three significant figures and include the appropriate units. B.What is the direction of the velocity of the 0.250-kg puck after the collision?C. What ise the speed of the 0.900-kg puck after the collision?Express your answer to three significant figures and include the appropriate units. D. What is the direction of the velocity of the 0.900-kg puck after the collision?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..