.125 kg piece of rubber slows down from 20 m/s to 10m/s as it slides along ice for 102 meters calculate the force of friction

-0.18 N

Explanation:

The motion of the piece of rubber is a uniformly accelerated motion, so we can find its acceleration using the suvat equation:

where:

v = 10 m/s is the final speed

u = 20 m/s is the initial speed

a is the acceleration

s = 102 m is the distance  covered

Solving for a,

The net force acting on the piece of rubber is the force of friction; according to Newton's second law of motion, the force is equal to the product of mass (m) and acceleration (a):

Here we have

m = 0.125 kg is the mass

Therefore, the force of friction is:

And the negative sign means the direction of the force is opposite to the direction of motion.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz